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Derive the equation of motion and find the steady state displacement of mass m.
1 Answer
written 5.8 years ago by |
ANSLOM,
m¨x = -k (x – y) – kx – c˙x
m¨x + c˙x + kx + k (x – y) = 0
m¨x + c˙x + kx + kx = ky
m¨x + c˙x + 2kx = ky sin wt
We know that
m¨x + c˙x + kx = Fo sin wt
Fo = ky
Keq = 2k
XXst=1√(1−r2)2+(2ξr)2
X=ky2k√(1−r2)2+(2ξr)2
XY=12√(1−r2)2+(2ξr)2