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Derive the equation of motion and find the steady state displacement of mass m.
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ANSLOM,

m¨x = -k (x – y) – kx – c˙x

m¨x + c˙x + kx + k (x – y) = 0

m¨x + c˙x + kx + kx = ky

m¨x + c˙x + 2kx = ky sin wt

We know that

m¨x + c˙x + kx = Fo sin wt

Fo = ky

Keq = 2k

XXst=1(1r2)2+(2ξr)2

X=ky2k(1r2)2+(2ξr)2

XY=12(1r2)2+(2ξr)2

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