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An accelerometer of natural frequency 200 Hz and damping ratio 0.7 is used to measure the vibration of a system
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whose actual disp. Is y(t) [1.65 sin 45.1)t] mm. What is the output of accelerometer?

$f_n$ = 200 Hz

$w_n = 2 \pi \times fn = 2 \times \pi \times 200 = 1256.63$ rad/sec.

$\xi= 0.7$

Y (t) = 1.65 sin 45.1 t - - - - (1)

Y (t) = y. sin wt - - - - (2)

Y = 1.65mm, W = 45.1 rad/sec

$\frac{\ddot{z}}{\ddot{y}} = \frac{1}{\sqrt{ (1-r^2)^2 + (2 \xi r)^2}}$

$r = \frac{45.1}{1256.63} = 0.03588$

$\frac{\ddot{z}}{(45.1)^2 \times (1.6)} = 1001$ [acceleration od m/c = $w^2 . y$]

$\ddot{z}$ = 3254.49 $mm/sec^2$

= 3.25 $m/sec^2$

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