(i) RMS output voltage can be obtained from

$$E_{0 \mathrm{rms}}=\left[\frac{2}{T / 2} \int_{0}^{T / 2} E^{2} \mathrm{d} t\right]^{1 / 2}$$

$$\therefore \quad E_{0 \operatorname{rms}}=E_{\mathrm{dc}}-----(1)$$

(ii) The instantaneous output voltage can be expressed in fourier series as

$$e_{0(wt)}=\sum_{n=1,3,5, \ldots}^{\infty} \frac{4 E_{\mathrm{dc}}}{n \pi} \sin n \omega t-----(2)$$

The output voltage waveform contains …