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Gyroscopic Effect on Shaft Rotating Inside Bearing:
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| written 6.4 years ago by |

$C = I_w. W_p$
$I = m k^2$
$I = \frac{mr^2}{2} = \frac{4 \times 0.075^2}{2} = 0.011 \ kgm^2$
$w = \frac{2 \pi \times 800}{60} = 83.7755 \ rad/sec$
$w_p = \frac{2 \pi Np}{60} = \frac{2 \pi \times 50}{60} = 5.23$ rad/sec
$C = 0.011 \times 83.7755 \times 5.23$
$C …