with $L = 0.36 \mu m$ and $W/L = 10$; it was fabricated in a $0.18- \mu m$ CMOS process for which $\mu_n C_ox = 387 \mu A/ V^2$ and $V^`_A = 5 V/ \mu m$. Find the values of $g_m$ and $A_0$ obtained at $I_D = 10 \mu A, 100 \mu A$ and $1 mA$.

Since,

$W/L = 10$ and $L = 0.36 \mu m$

Therefore, $W = 3.6 \mu m$

For CS Amplifier :-

$g_m = \sqrt {2 \mu_n C_{ox} (W/L) I_D}$

$A_o = \dfrac {V^`_A \sqrt {2 \mu_n C_{ox} (WL)}}{\sqrt I_D} $

(i) For $I_D = 10 \mu A,$

$g_m = \sqrt {(2)(387 …