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The maximum daily demand of water is 6 MLD. Design a plain sedimentation tank rectangular in shape, assuming detention time of 4 hours and flow through velocity of 20 cm/minute.check the flow rate
written 6.3 years ago by gravatar for teamques10 teamques10 ★ 70k modified 3.6 years ago by gravatar for Chandan15 Chandan15 • 300
environmental engineering
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written 3.6 years ago by gravatar for Chandan15 Chandan15 • 300

Solution :

Data : Daily demand = 6 MLD, Detention time = 4 hours. Flow through velocity = 20 cm/min.

  1. Water to be treated per hour =$\frac{6*10^6}{24}$= 0.25 x 106 lit/hr.

  2. Capacity of sedimentation tank = Hourly demand x D.T = 0.25 x 1$0^6$ x4=1$0^6$lit=1000$m^3$

  3. Length of the tank = …

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