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| written 6.3 years ago by |

Drilling:
D = 10 mm
Cutting speed V=18 m/min
Spindle speed = $\frac{320 V}{D}$ = 576 rpm
Assume, Feed = 0.2 mm/rev
$\quad$ = 0.2 $\times$ mm/rev = 0.2 $\times$576
$\quad$ = 115 mm/min
Milling:
D = 6 mm
Cutting speed V=15 m/min
Spindle speed =$\frac{320 V}{D}$ = 800 rpm …