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Find the equation of the line passing through (3,-4) and having slope $\frac{3}{2}$

written 6.3 years ago by teamques10 ★ 70k

modified 3.7 years ago by krithikkm200 • 10

engineering mathematics

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1 Answer

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written 6.3 years ago by teamques10 ★ 70k

Solution:

Point $ =\left(x_{1}, y_{1}\right)=(3,-4) \quad \& slope =\frac{3}{2}$

$\therefore equation of line is,$

$\quad y-y_{1}=m\left(x-x_{1}\right)$

$\therefore y - (-4) = \frac{3}{2}(x-3)$

$\therefore 2(y+4) = 3(x-3)$

$\therefore 3x - 3y -17 = 0$

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