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If $\tan A=\frac{1}{2}, \tan B=\frac{1}{3}, find the value of \tan (A+B)$

written 6.3 years ago by teamques10 ★ 70k

modified 3.7 years ago by krithikkm200 • 10

engineering mathematics

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written 6.3 years ago by teamques10 ★ 70k

Solution:

\begin{aligned} \tan (A+B) &=\frac{\tan A+\tan B}{1-\tan A \tan B} \ &=\frac{\frac{1}{2}+\frac{1}{3}}{1-\left(\frac{1}{2}\right)\left(\frac{1}{3}\right)} \ &=1 \end{aligned}

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