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Find the equation of straight line passes through the points (-4,6) and (8, -3)

written 5.6 years ago by teamques10 ★ 69k

modified 3.1 years ago by DevarenjiniP • 3.2k

engineering mathematics

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2 Answers

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written 5.6 years ago by teamques10 ★ 69k

•   modified 5.6 years ago

Solution:

$Let \left(x_{1}, y_{1}\right)=(-4,6) and \left(x_{2}, y_{2}\right)=(8,-3)$

Equation of line is,

$\frac{y-y_{1}}{y_{1}-y_{2}}=\frac{x-x_{1}}{x_{1}-x_{2}}$

$\therefore \frac{y-6}{6+3}=\frac{x+4}{-4-8}$

$\therefore \frac{y-6}{9}=\frac{x+4}{-12}$

$\therefore-12 y+72=9 x+36$

$\therefore 9 x+12 y-36=0$

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written 3.1 years ago by dhamodapra428 • 20

Straight line passes through the point

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