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Find the equation of line passing through the point (2,5) and through the intersection of the lines x+y = 0, and 2x-y=9.

written 6.3 years ago by teamques10 ★ 70k

modified 3.7 years ago by krithikkm200 • 10

engineering mathematics

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1 Answer

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written 6.3 years ago by teamques10 ★ 70k

Solution:

$Let (x_{1},y_{1}) = (2,5)$

x`+ y = 0

2x - y = 9

3x = 9

x = 3

y = -3

$(x_{2},y_{2} = (3,-3)$

Equation of line is ,

\begin{array}{l}{\frac{y-y_{1}}{y_{1}-y_{2}}=\frac{x-x_{1}}{x_{1}-x_{2}}} \ { : \frac{y-5}{5+3}=\frac{x-2}{2-3}} \ \therefore \frac{y-5}{8}=\frac{x-2}{-1} \end{array}

-y+5 = 8x-16

8x+y - 21 = 0

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