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Find the mean deviation from mean of the following distribution.
written 4.7 years ago by | • modified 4.7 years ago |
C.I | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
---|---|---|---|---|---|
$F_{i}$ | 5 | 8 | 15 | 16 | 6 |
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written 4.7 years ago by | • modified 4.7 years ago |
C.I | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
---|---|---|---|---|---|
$F_{i}$ | 5 | 8 | 15 | 16 | 6 |
written 4.7 years ago by |
Solution:
C.I | $f_{i}$ | $x_{i}$ | $f_{I}x_{i}$ | $d_{I}=|x_{I}-\bar{x}|$ | $f_{I}d_{i}$ |
---|---|---|---|---|---|
0-10 | 5 | 5 | 25 | 22 | 110 |
10-20 | 8 | 15 | 120 | 12 | 96 |
20-30 | 15 | 25 | 375 | 2 | 30 |
30-40 | 16 | 35 | 560 | 8 | 128 |
40-50 | 6 | 45 | 270 | 18 | 108 |
$\sum f_{I}=50$ | $\sum f_{i} x_{I}=1350$ | $\sum f_{i} d_{i}=472$ |
$\operatorname{Mean} \overline{x}=\frac{\sum f_{i} x_{i}}{\sum f_{i}}$
$\therefore \overline{x}=\frac{1350}{50}$
$\therefore \overline{x}=27$
$M \cdot D=\frac{\sum f_{i} d_{i}}{f_{i}}$
$\therefore M \cdot D=\frac{472}{50}$
$\therefore M \cdot D .=9.44$