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Calculate the safe stopping sight distance for a design speed of 50 Kmph for a two way traffic in a single lane road. Assume f = 0.37 and reaction time = 2.5 seconds.
1 Answer
written 4.7 years ago by |
Given data:
V = 50 Kmph
t = 2.5 seconds
f = 0.37
SSD = 0.278 V t + ( V2/ 254 f)
= (0.278 x 50 x 2.5 ) + ( 502/ ( 254 x 0.37))
= 34.75 + 26.60
SSD = 61.35 m. for …