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Design the rate of super elevation for a Horizontal Highway curve of radius 500 metres and speed 100 Kmph. Assume suitable data.

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Design the rate of super elevation for a Horizontal Highway curve of radius 500 metres and speed 100 Kmph. Assume suitable data.

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written 4.6 years ago by |

Given data;

V = 100 Kmph

R = 500 meter

For mixed traffic conditions, Super elevation is given by formula for maximum super elevation:

e = V^{2}/ (225 x R)

= 100^{2}/ (225 x 500)

= 0.089 m per meter of carriage way OR

= 0.089 x 100

= 8.9 % > 7 % (Restricted for Plain terrain)

Provide maximum super elevation = e = 7 % i.e. = 0.07

Now, Check for coefficient of lateral friction developed for full speed using the Primary or Actual equation

e + f = V^{2}/ (127 x R)

0.07 + f = 100^{2}/ (127 x 500)

0.07 + f = 0.157

f = 0.157 – 0.07

f = 0.087 < 0.15 (restricted for design purpose)

Hence, the design is safe with a super elevation of e = 0.07 m per meter length carriage way.

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