written 4.6 years ago by | modified 23 months ago by |

The design speed of the Road is 60 kmph. Assume Reaction time of the driver as 2.5 sec and Co-efficient of friction as 0.6. Brake efficiency is 50%.

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Calculate the Stopping Sight Distance for two way traffic in a Single Lane Road

written 4.6 years ago by | modified 23 months ago by |

The design speed of the Road is 60 kmph. Assume Reaction time of the driver as 2.5 sec and Co-efficient of friction as 0.6. Brake efficiency is 50%.

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written 4.6 years ago by |

Given data:

V = 60 Kmph

t = 2.5 seconds

f = 0.6 and brake efficiency is 50%

As the brake efficiency is 50% the wheels will skid through 50% of the braking distance and rotate through the remaining distance. Therefore, the value of coefficient of friction developed (f) may be taken as 50% of the coefficient of friction,

i.e. f = (50/100) x 0.6 = 0.3

SSD = 0.278 V t + ( V^{2} / 254 f)

= (0.278 x 60 x 2.5 ) + ( 60^{2}/ ( 254 x 0.3))

= 41.70 + 47.24

SSD = 88.94 m. for one way traffic.

SSD for Two Way traffic on single lane road = 2 x SSD for one way traffic

= 2 x 88.94 m

= 177.88 m say 178 m.

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