A solid shaft of diameter 110 mm transmits a torque of 12.5 kN.m. Calculate maximum shear stress in material of shaft and angle of twist in radians for a length of 2.5 m. Take G = 80 GPa.

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teamques10 ★ 70k

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written 6.2 years ago by

teamques10 ★ 70k

Given: For solid shaft, d = 110 mm , R = 55 mm, T = 12.5 kN-m = $12.5 \times 10^{6} N-mm$ , L = 2.5m = 2500 mm, G = 80 GPa = $80 \times 10^{3} N/mm^{2}$

Solution:

$Polar M.I = I_{p} = \frac{\pi}{32} d^{4} = \frac{\pi}{32} \times 110^{4} …

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