Given: For offset link, d = 30 mm , $\sigma_{Max} = 80 N/mm^{2}$

Eccentricity = e = 40 + $\frac{d}{2}$ = 40 + $\frac{30}{2}$ = 55mm.

Solution:

$c/s Area = A = \frac{\pi}{4} \times d^{2} = \frac{\pi}{4} \times 30^{2} = 706.86 mm^{2}$

$M.I = I = \frac{\pi}{64} \times d^{4} = …