0
A mild steel link as shown in Figure No. 2, by full lines transmits a pull of 80 kN; find the dimensions b and t if b = 3t. Assume the permissible stress as 70 N/mm2.

enter image description here

somd-2 • 103  views
0  upvotes
0

Given:

For M.S link, P = 80 kN = $80 \times 10^{3}$ , b = 3t , $\sigma = 70 N/mm^{2}$

Solution:

$\sigma = \frac{P}{A}$ $\therefore A = \frac{P}{\sigma} = \frac{80 \times 10^{3}}{70}$

$\therefore A = 1142.86 mm^{2}$

$\therefore A = 1142.86$

$\therefore 3t \times t = 1142.86$

$\therefore t = 19.52 mm$

& b = 3t = $3 \times 19.52 = 58.56 mm$

0  upvotes
Please log in to add an answer.

Next up

Read More Questions

If you are looking for answer to specific questions, you can search them here. We'll find the best answer for you.

Search

Study Full Subject

If you are looking for good study material, you can checkout our subjects. Hundreds of important topics are covered in them.

Know More