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Determine the diameter of a solid steel shaft which will transmit 90 kW at 160 rpm. Also find the length of the shaft if the twist must not exceed $1^{o}$ over the entire length.
written 6.2 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 6.2 years ago

The maximum shear stress is limited to 60 N/mm2. Take the value of modulus of rigidity = 8 × 104 N/mm2.
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written 6.2 years ago by gravatar for teamques10 teamques10 ★ 70k •   modified 6.2 years ago

Given:

For Solid circular steel shaft-

p = 90 kW = $90 \times 10^{3} watts$,

N = 160 rpm , $q_{max} = 60 N/mm^{2}$,

$G = 8 \times 10^{4} N/mm^{2}$

$\theta = a^{o} = 1 \times \frac{\pi}{180} = 0.0175 rad$

Solution:

$P = \frac{2 \pi N T_{avg}}{60}$

$90 \times 10^{3} …

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