A steel flat 30mm x 15mm and 2.8m long is subjected to an axial pull of 58kn, if $E = 2 \times 10^{5} N/mm^{2}$ and $\mu = 0.30$. Calculate volumetric strain and change in Volume.

Welcome back.

and 5 others joined a min ago.

1.3kviews

written 4.7 years ago by

teamques10 ★ 65k

modified 2.1 years ago by

pedsangini276 • 4.8k

strength of materials

ADD COMMENT EDIT

1 Answer

17views

written 4.7 years ago by

teamques10 ★ 65k

• modified 2.5 years ago

$$ \begin{array}{l}{\text { Data: } b=30 m m, t=15 m m, L=2.8 m, P=58 \mathrm{kN}, E=2.1 \times 10^{3} \mathrm{N} / \mathrm{mm}^{2},} \ {\mu=0.30} \ {\text { Find: } e_{v}, \delta v} \ {\sigma=\frac{P}{A}=\frac{58 \times 10^{3}}{30 \times 15}=128.88 \mathrm{N} / \mathrm{mm}^{2}}\end{array} $$ $$ \begin{array}{l}{\mathrm{e}_{\mathrm{v}}=\frac{\sigma}{\mathrm{E}}(1-2 \mu)} \ {\mathrm{e}_{\mathrm{v}}=\frac{128.88}{2.1 \times 10^{3}} \times(1-2 \times …

Create a free account to keep reading this post.

and 4 others joined a min ago.

ADD COMMENT EDIT

Community

Content

Company