A chord is used to lower vertically a block of mass $M$ a distance $d$ at a constant downward acceleration of $\displaystyle{\frac{g}{4}}$ .Then, what is the work done?

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written 7.8 years ago by

anjijose.09 • 0

modified 2.2 years ago by

sagarkolekar ★ 11k

engineering physics

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1 Answer

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written 7.8 years ago by

ebin371 • 20

modified 7.8 years ago by

sanketshingote • 100

Explanation : Tension in the code is

$$T=M\left[g-\displaystyle{\frac{g}{4}}\right]=\frac{3Mg}{4}$$

in upward direction,since chord is displaced in the downward direction ,so

$$W=T.d = -\frac{3Mgd}{4}$$

Here,negative sign shows that T and d are in the opposite direction.

Work done is $\boxed{ W= \frac{3Mgd}{4}} $

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