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Calculate all types of hardness of water sample containing: Ca(HCO3)2=81 ppm MgSO4=60 ppm, MgCO3=42 ppm, Ca(NO3)2=82 ppm.
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CONSTITUENTS QUANTITY IN ppm MULTIPLICATION FACTOR CaCO3 EQUIVALENT
Ca(HCO3)2 81 $\dfrac{100}{162}$ $\dfrac{81 \times 100}{162}=50$
MgSO4 60 $\dfrac{100}{120}$ $\dfrac{60 \times 100}{120}=50$
MgCO3 42 $\dfrac{100}{84}$ $\dfrac{42 \times 100}{84}=50$
Ca(NO3)2 82 $\dfrac{100}{164}$ $\dfrac{82 \times 100}{164}=50$

 

Temporary hardness = Hardness caused due to[Ca(HCO3)2 + MgCO3] $= 50 + 50 =100 \ \mathrm {ppm}$

Permanent hardness = Hardness caused due to[MgSO4 + Ca(NO3)2 $= 50 + 50 =100 \ \mathrm {ppm}$

Total hardness = Temporary hardness + Permanent hardness $=100 + 100 =200\ \mathrm {ppm}$

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