and 2 others joined a min ago.
0
19kviews
Calculate temporary, permanent and total hardness of water sample containing
Mg(HCO3)2 = 7.3 ppm, Ca(HCO3)2 = 16.2 ppm, MgCl2 = 9.5 ppm, CaSO4 = 13.6 ppm
1 Answer
0
5.4kviews
written 3.2 years ago by
teamques10
★ 66k
|
Temporary hardness causing Impurities = Mg(HCO3 )2, Ca(HCO3 )2
Permanent hardness causing Impurities = MgCl2, CaSO4
Hence,
Temporary hardness = 7.3 + 16.2 = 23.5 ppm
Permanent hardness = 9.5 + 13.6 = 23.1 ppm
Total Hardness = 23.5 + 23.1 = 46.6 ppm
ADD COMMENT
EDIT
Please log in to add an answer.