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A body is projected vertically upwards. If $t_1$ and $t_2$ be the instants at which it is at a height $h$ above the point of projection, while ascending and descending respectively.Then find $h$ !!
written 9.5 years ago by gravatar for ebin371 ebin371 • 20 modified 4.1 years ago by gravatar for Sharad Sharad • 160
engineering physics
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written 4.1 years ago by gravatar for Sharad Sharad • 160 •   modified 4.0 years ago
  • u = velocity of projection (upward).
  • s = displacement after time t = h
  • a = acceleration (downward) = - g

$Using, s=u t+\frac{1}{2} a t^{2}$ We have,

$h = u t - \frac{1}{2} g t² $

2h = 2ut - gt²

gt² - 2ut + 2h = 0 . …

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Improve formatting, take help of team

4.1 years ago by prakhar1144 ★ 5.0k
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