and 4 others joined a min ago.
0
850views
15,000 litres of hard water was passed through a zeolite softener. The exhausted zeolite required 120 litres of NaCl having 30 g/litre of NaCl. Calculate the hardness of water.
1 Answer
0
20views
written 3.2 years ago by
teamques10
★ 66k
|
1L NaCl contain = 30 g
120 L NaCl contain = 120 × 30 g
Thus, the amount of substance (W) = 3600 g
Equivalent mass of Na = 23
Equivalent mass of Cl = 35.5
Hence, equivalent mass of NaCl (E) = 58.5
Equivalent of CaCO3 = (W × 50)/E
= (3600× 50)/58.5
= 3076.9 g of CaCO3
which means
15000 L of water = 3076.9 g of CaCO3
= 3076.9 × 1000 g of CaCO3
Hence, 1 L water = 3076.9 × 1000 / 15000
= 205.12 ppm CaCO3
Hardness of Water Sample = 205 ppm
ADD COMMENT
EDIT
Please log in to add an answer.