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If y=sinθ+cos θ then prove that \[y_n = r^n \sqrt{1+(-1)^n \sin 2 \theta} \] where θ rx
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teamques10
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$y= sin rx + cos rx \; \; \; \; \; ( \theta = rx) \\ \text {Using the result of nth derivative of sin ax and cos ax we get,} \\ \therefore y_n = r^n \bigg [ sin \bigg(rx + {n\pi \over 2} \bigg)+ cos \bigg( rx +{n\pi \over …
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