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An Ultrasonic sound wave is used to detect the position of defect in a steel bar of thickness 50 cm. if the echo times are 40 and 90 ?-sec. Locate the position of defect.
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Given –

$d_2=50cm$

$\Delta t_1=40 \mu sec, \Delta t_2=90 \mu sec$

Solution –

Let $d_1$ be the location of defect & $d_2$ be the thickness of steel bar.

Let $\Delta t_1$ be echo time from defect & $\Delta t_2$ be the echo time for rod.

Now, we know that,

$d=\dfrac …

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