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A class room has dimension 20 x 15 x 10 m3, the reverberation time is 3 sec. calculate total absorption of its surfaces and average absorption coefficient.
1 Answer
written 3.0 years ago by |
Given –
$V=20\times 15 \times 10m^{3}$
$T=3 sec$
Solution –
We know that
1) $T=0.161\times \dfrac {V}{\sum aS}$
$\sum aS=0.161 \times \dfrac {(20\times 15 \times 10 )}{3}$
$\sum aS =80.5 $ Sabines
2) $a=\dfrac {\sum aS}{\sum S}= \dfrac {80.5}{2(20\times 15 +15 \times 10 + 10 \times 20)} =0.062$
∴ Total …