written 4.5 years ago by
teamques10
★ 70k
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modified 2.9 years ago
by
prashantgoswami83232
• 10
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Given Data:
Supply voltage, $V=200\ Volts$
Supply frequency, $f=50Hz$
Resistance, $R=10\ \Omega$
Inductance, $L=50mH = 40\times 10^{-3}\ Henry$
Let's consider a coil connected to AC supply as shown in figure below-
(i) Impedance of Coil:-
As the Impedance of a coils for AC supply is given by,$Z=R+j(X_L)=R+j\omega L=R+j2\pi f L$ …
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