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A force of magnitude 500N is acting from A(2,3,6) and passes through a point B(6,2,6). Compute its moment about point C(4,6,3).
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written 2.9 years ago by
teamques10
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Force Vector
$F=(500)\dfrac{AB}{|AB|}=500\dfrac{(4i-j+0k)}{\sqrt{4^2+(-1)^2+0}}=121.27(4i-j)\ \ \ \ N$
Moment of Force about Point C
$M_C=CA\times F$
$M_A=121.27\left[\begin{matrix} i&j&k\\ (2-4)&(3-6)&(6-3)\\ 4&-1&0 \end{matrix}\right]\\ =121.27\left[\begin{matrix} i&j&k\\ -2&-3&3\\ 4&-1&0 \end{matrix}\right]\\ =363.81i-1455.24j+1697.78k\ \ \ \ (N.m)$
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