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A prismatic bar AB of length 6m and weight 3KN is hinged to a wall and supported by cable BC. Find hinge reaction and tension in cable BC.
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written 3.0 years ago by
teamques10
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Answer:
Applying Lamis Theorem
$\dfrac{T_{BC}}{sin 90^{\circ}}=\dfrac{R_A}{Sin150^{\circ}}=\dfrac{3}{Sin120^{\circ}}$
$\dfrac{T_{BC}}{sin 90^{\circ}}=\dfrac{3}{Sin120^{\circ}}$
$Tension\ in \ cable\ BC\ (T_{BC})=\dfrac{3}{Sin120^{\circ}}\times Sin150^{\circ}=2\sqrt{3} \ KN$
$\dfrac{R_A}{Sin150^{\circ}}=\dfrac{3}{Sin120^{\circ}}$
$Hinge \ reaction\ (R_A)=\dfrac{3}{Sin120^{\circ}}\times Sin150^{\circ}=\sqrt{3}\ \ KN$
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