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Find force requires to pull block B as shown. Coefficient of friction between A and B is 0.3 and between B and floor is 0.25. Mass of A=40kg and B=60kg.
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From Free Body Diagram of Block A

 

Applying static equillibrium equation in y direction,

$\sum F_y = 0 \\ \therefore N_A - 40\times 9.81 + T \sin{30 }= 0 \\ \therefore N_A + 0.5T = 392.4$

 

Also for x direction,

$\sum{F_x} = 0 \\ \therefore 0.3N_A- T \cos{30} = 0 …

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