and 4 others joined a min ago.
0
1.8kviews
A particle travels on a circular path, whose distance travelled is defined by S=(0.5t3+3t)m. If the total acceleration is 10 m/s2, at t=2 sec, find its radius of curvature.
1 Answer
0
332views
written 3.0 years ago by
teamques10
★ 65k
|
To answer this question we should know following key points:
1. Total Acceleration is given as $a_{total}=\sqrt{\left(a_t\right)^2+\left(a_n\right)^2}$
2. $a_t=\dfrac{dv}{dt} \text{ and } a_n=\dfrac{v^2}{\rho}$
Here, $s=0.5t^3+3t \text{ m }$
$\therefore v=\dfrac{ds}{dt}=1.5t^2+3 \text{ m/s}$
and
$a_t=\dfrac{dv}{dt}=3t \text{ m/$s^2$}$ Hence, at t = 2 sec, $v=1.52^2+2=9 \text{ m/s }$ and $a_t=32=6 …
ADD COMMENT
EDIT
Please log in to add an answer.