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A particle is projected with an initial velocity of 2m/s along a straight line. The relation between acceleration and time is given in the diagram. Draw v-t and s-t diagram.
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Area under a-t graph gives the velocity.

Velocity:

Part AB on a-t graph represents linearly decreasing acceleration.

Give $v_0 = 2 \ m/s$

$v_4 = v_0 + A(\Delta OAB)= 2 + \dfrac {1}{2} \times 4 \times 2 = 6 \ m/s$

Part BC on a-t graph represents linearly increasing acceleration. …

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