Given:

u=0

t1=5.45

t2=?

speed=v=?

Solution:

(i) Acceleration motion:

$v=u+at=5.4a\rightarrow(1)$

also,

$v^2=u^2+2as=2\times a \times 35=70a\rightarrow (2)$

put (1) in (2),

$(5.4a)^2=70a\implies a=2.4m/s^2$

$\therefore v=12.96m/s$

(ii) Uniform velocity:

$x=100-35=65m;v=12.96m/s\\[2ex] \therefore t=\dfrac{x}{v}=\dfrac{65}{12.96}=5s\\[2ex] \therefore t=t_1=t_2=5.4+5=10.4s$