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A vertical lift of total mass 750 kg acquires an upward velocity of 3m/s over a distance of 4m moving with constant acceleration starting from rest. Calculate the tension in the cable.
1 Answer
written 2.9 years ago by |
Given:
$m=750 kg$
$u=0 m/s$
$v=3 m/s $
$S=4m$
$a=constant$
$v^2=u^2+2aS $
${\left(3\right)}^2=0+2\times{}a\times{}\left(4\right) $
$\therefore{}a=1.125\ m/s^2\ \uparrow{} $
Applying D’Alemberts Principle -
$\displaystyle\sum F_y=0 $
$T-ma-mg=0 $
$\therefore{}T=m(a+g) $
$=750\times{}(1.125+9.81) $
$T=8201.25\ N $