This configuration is a emitter unbypassed configuration

The input impedance is given by the formula

$Z_{i} = R_{B}||Z_{b}$

$Z_{b} = \beta R_{E}$

$\beta_{re}=6800$

$r_{e}$=$\dfrac{6800}{140}=38.5,$

From the figure it is clear that Emitter resistance is zero

$R_{E}$=0;

$Z_{i}$=120+68=188$K\Omega$

The output impedance of bypassed emitter  resistance BJT transistor is given by 

$Z_{o}=R_{c}$

$Z_{0}=3K\Omega$

The gain of a emitter resistance bypassed BJT Transistor is given by

$A_{v}=\dfrac{Vo}{Vi}=\dfrac{-\beta R_{c}}{(R_{E}+r_{e})}$

here RE=0

$A_{v}=-\beta \dfrac{R_{c}}{r_{e}}$

    =$-140(\dfrac{3000}{38.5})$

    =-1.7

The negative sign in the gain equation reveals a 180 degreephase shift between input and output