The base Voltage of Voltage Divider Configuration is given by

$V_B=V_{th}=V_{CC}\dfrac{R_2}{R_1+R_2}$

The Collector current is given by the formula

$I_c=\beta I_b$

Hence the base current is given by

$I_b=0.4mA$

Applying KVL in clockwise direction in Collector Emitter Junction we have

$V_{CE}=V_{CC}-I_cR_c-I_ER_E$

$12=24-9.4-(2.4 \times10^{-3}R_E)$

The Emitter Resistance is given by

$R_E=\dfrac{-2.6 …