Solution :

As the coefficient matrix is not diagonally dominant we rearrange the equations

$$ \begin{array}{l} 28 x+4 y-z=32 \\ 2 x+17 y+4 z=35 \\ x+3 y+10 z=24 \end{array} $$

Since the diagonal elements are dominant in the coefficient matrix, we write $\mathrm{x},\mathrm{y}, \mathrm{z}$ as follows:

$$ \begin{aligned} x &=\frac{1}{28} …