0
1.6kviews
Describe open loop and closed loop system of power control in a CDMA system
1 Answer
0
44views

The Open Loop Power Control require in CDMA is due to following reason.

  • Assumes Loss is Similar on Forward paths and Reverse Paths
  • Receive Power + Transmit Power = -73
  1. All Powers in dBm
  • Example: For a Received Power of -85 dBm
  1. Transmit Power = (-73) – (- 85)
  2. Transmit …

Create a free account to keep reading this post.

and 2 others joined a min ago.

Please log in to add an answer.