Incident optical power

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Incident optical power

written 7.8 years ago by

teamques10 ★ 64k

• modified 7.8 years ago

A photodiode has quantum efficiency of 65% when a photon of energy of $1.5 x 10^{-19}J$ are incident upon it. At what wavelength is the photodiode operating?

Calculate the incident optical power required to operate photo current of 2.5 µA when the photodiode is operating as above.

Mumbai University > Electronics Engineering > Sem7 > Optical Fiber Communication

Marks: 10M

Year: May 2014

optical fiber communication

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written 7.8 years ago by

teamques10 ★ 64k

Given: $η=65\%=0.65$

$$E_p= 1.5 ×10^{-19}J \\ \; \\ I_p= 2.5 µA \\ \; \\ $$

To find: Operating wavelength λ

Incident optical power ${P_{in}}$

Solution:

$R = \frac{ɳqλ}{hc} \\ \; \\ hν = E_p and ν= \frac{c}λ \\ \; \\ λ= \frac{ hc}{E_p} = \frac{6.62×10^{-34}∙3×10^8}{1.5 ×10^{-19} }=0.21µm \\ \; \\ ∴ λ=1.324 µm \\ \; \\ R =\frac{ɳq}{hν}= \frac{ɳq}{E_p} = \frac{0.65 × 1.6 ×10^{-19} }{1.5 ×10^{-19} }= 0.69 ∴ R=0.69 \\ \; \\ R = \frac{I_p}{P_{in}} = \frac{2.5×10^{-6}}P_{in} =0.69 \\ \; \\ ∴ P_{in}=3.6 µW \\ \; \\ $

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