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Reduce the matrix A to normal form and hence find its rank where $ \left[ \begin{array}{cccc}1&-1& 3& 6\\1& 3&-3 &-4\\5& 3 & 3 & 11\end{array}\right] $
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written 7.9 years ago by
teamques10
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A=$ \left[ \begin{array}{cccc} 1&-1& 3& 6 \\ 1& 3&-3 &-4 \\ 5& 3 & 3 & 11 \end{array}\right] \\ \; \\ \; \\ \; \\ R_2 \rightarrow R_2-R_1 \; , \; R_3 \rightarrow R_3 -5R_1 \\ \; \\ \; \\ \therefore A= \left[ \begin{array}{cccc} 1&-1& 3& 6 \\ 0& 4&-6 …
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