**Given:**

**Q= 200 TR**

**T1= -6 ° C = -6+273=267 K**

**T2= 25° C**

**Mass of ice produced per day**

*We know that heat extraction capacity of the refrigerator*

= 200 x 210 = 42000 kI/min

*Heat removed from 1 kg of water at 25°C to form ice at 0°C
(1 TR=210 kJ/min)*

= Mass x Sp. heat x Rise in temperature + hfg (ice)

= 1 x 4.187 (25-0) +335 = 439.7 ki/kg

*Mass of ice produced per min*

= $\frac{42000 }{95.52}$

= 97 7552 Kg/min

*and mass of ice produced per day = 95.52 x 60 x 24 = 137550 kg = 137.55 tonnes*

**Power required to drive the unit**

*We know that C.O.P. of the reversed Carnot cycle*

$\frac {T_1 }{T_2-T_1} $ =${267}{ 298-267}=8.6$

COP. = $ \cfrac {Heat extraction capacity}{Work done per mm} $

Work done per min = 42 000/8.6 = 4884 kJ/min

**Power required to drive the unit**

$= \frac{4884}{60}$
=81.4 kW