Ask
Login
0
554views
Calculate the shear stress at the neutral axis in a beam of triangular section with a base of 40 mm and height 20 mm, subjected to a shear force of 3 kN.
written 2.4 years ago by gravatar for bhoral455 bhoral455 • 20 modified 2.1 years ago by gravatar for Chandan15 Chandan15 • 300
strength of materials
ADD COMMENT EDIT
1 Answer
0
7views
written 2.1 years ago by gravatar for Chandan15 Chandan15 • 300 •   modified 2.1 years ago

Shear Stress at Neutral Axis in case of triangle

$\tau_{N A}$ (triangle) $=\frac{4}{3}$ ×τavg $=\frac{4}{3} \times \frac{2 V}{D h}$ $V=3 \mathrm{KN}, b=40 \mathrm{~mm}, h=20 \mathrm{~mm}$ $τ_{N A}=\frac{4}{3} \times \frac{2 \times 3 \times 103}{40 \times 20}=10 \mathrm{~N} / \mathrm{mm}^{2}$

Create a free account to keep reading this post.

and 2 others joined a min ago.

ADD COMMENT EDIT
Please log in to add an answer.