Solution :

Let , $X_A$ and $Y_A$ be the reactions at the hinge A and $R_B$ at the roller support B

F.B.D of given structure

Applying conditions of equilibrium

$1) \Sigma F_x =0$

$\therefore H_A-30cos40°=0 $

$\therefore H_A=22.98 KN$

$\space $

$2) \Sigma M_A^F =0$

$\therefore 10R_B-(5\times4\times2)-(25\times4)-(8\times 30sin40°)=0 $

$\therefore …