Find the vertical and horizontal deflections of the joint E of the truss shown in figure. Area of each horizontal member = 1200 mm^2; Area of other members = 1500 mm². Modulus of elasticity= 200KN/mm^2

Given Data:-

• A_horizontal $=1200 \mathrm{~mm}^{2}$
• $A_{\text {other member }}=1500 \mathrm{~mm}^{2}$
• Modulus of Elasticity, $E=200 \mathrm{~kN} / \mathrm{mm}^{2}$
• $ \sum V=0$

$\Rightarrow R_{A}+R_{D}=180 \mathrm{kN}$

• $\sum M_{A}=0$

$-\left(R_{D} \times 6\right)+(120 \times 1.5)+(60 \times 4.5)=0$

• $R_{D}=75 \mathrm{KN}$
• $R_{A}=105 \mathrm{KN}$
• $F_{A B}=R_{A} \operatorname{cosec} 60^{\circ}=105 \times \frac{2}{\sqrt{3}}=121.24 \mathrm{kN}$ (C)
• $F_{A E}=R_{A} \cot 60^{\circ}=105 \times \frac{1}{\sqrt{3}}=60.62 …