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Show that $\triangledown =1-E^{-1}$

Mumbai University > First Year Engineering > sem 2 > Applied Maths 2

Marks : 3

Year : MAY 2015

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By definition

$E^{-1}f(x)=f(x-h)-(1)\\ \&\space \space \triangledown f(x)=f(x)-f(x-h)\\ \therefore f(x)=f(x)-E^{-1}f(x) \hspace {1cm} ........................(1)\\ \therefore \triangledown f(x)=(1-E^{-1})f(x)\\ \therefore \triangledown=1-E^{-1}$

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