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Realize Cauer Form $-1$ and Cauer Form $-2$ of the following function. $ z(s)=\frac{(S+1)(S+3)}{(s)(S+2)} $
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written 19 months ago by
prajapatijaimin
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Solution:
$ z(s)=\frac{(s+1)(s+3)}{(s)(s+2)}=\frac{s^2+4 s+3}{s^2+2 s}--------(1) \\ $
$ \text { Cauer-1 form - Using C.F.D. } $
$ \begin{aligned} \\ \therefore z_1(S) &=1 \\\\ y_2(s) &=\frac{1}{2} S \\\\ z_3(s) &=4 \\\\ y_4(S) &=\frac{1}{6} S \\ \end{aligned} \\ $
$ \text { Hence circuit in cauer-1 form is } \\ $ …
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