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The voltage $V(s)$ of network is given by $v(s)=\frac{3 s}{(s+2)\left(s^2+2 s+2\right)}$ plot it's pole zero diagram and hence obtain v(t)
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written 19 months ago by
prajapatijaimin
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• modified 19 months ago |
Solution:
Given $ \quad V(s)=\frac{3 s}{(s+2)\left(s^2+2 s+2\right)}...(1) $
zeros $ \Rightarrow S=0 $
poles $ \Rightarrow s=-2, S=-1+j 1, S=-1-j 1 $
By pole zero diagram, & eq $-^n$ (1) partial fraction expansion is:
$ V(s)=\frac{A}{s+2}+\frac{B}{(s+1-1 j)}+\frac{C}{(s+1+1 j)}...(2) \\ $
$ \begin{aligned} \\ A &=\frac{3\left(\overline{O P_1}\right)}{\left(P_2 \bar{P}_1\right)\left(\overline{\left.P_3 P_1\right)}\right.} \\\\ &\left.=\frac{3(21180)}{(\sqrt{2}(-135)(\sqrt{2} …
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