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Design a Composite low pass filter by image parameter method for following specifications: $R_0= 50 \Omega, f_c=50 \mathrm{MH}_2, f_{\infty}=52 \ \mathrm{MH}_2$
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written 19 months ago by
prajapatijaimin
• 3.1k
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Solution:
$ z_0=R_0=\sqrt{\frac{L}{C}}=50 \Omega \\ $
with constant $-k$ section low pass filter,
$ \begin{aligned} \\ & W_C=\frac{2}{\sqrt{L C}}=2 \pi \mathrm{fC}_C \\\\ \therefore & 2 \pi \times 50 M H_2=\frac{2}{\sqrt{L C}} \Rightarrow 50 \pi \times 10^6=\frac{1}{\sqrt{L C}}\\ \\ \therefore \quad & \sqrt{L C}=\frac{1}{50 \pi \times 10^6} \quad \therefore L C=4.05 …
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